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4c^2-72=-24c
We move all terms to the left:
4c^2-72-(-24c)=0
We get rid of parentheses
4c^2+24c-72=0
a = 4; b = 24; c = -72;
Δ = b2-4ac
Δ = 242-4·4·(-72)
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24\sqrt{3}}{2*4}=\frac{-24-24\sqrt{3}}{8} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24\sqrt{3}}{2*4}=\frac{-24+24\sqrt{3}}{8} $
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